4x^2+32x-17=0

Solution for 4x^2+32x-17=0 equation:

4x^2+32x-17=0

a = 4; b = 32; c = -17;
Δ = b2-4ac
Δ = 322-4·4·(-17)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-36}{2*4}=\frac{-68}{8}
=-8+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+36}{2*4}=\frac{4}{8}
=1/2
$